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1220222440113 = 32857142366403
BaseRepresentation
bin10001110000011010111…
…011001101001010110001
311022122121101210111200220
4101300122323031022301
5124443003421040423
62332321253403253
7154105151415255
oct21603273151261
94278541714626
101220222440113
11430547835716
121785a2039529
138b0b30a58c1
14430b8194265
1521b1a2449e3
hex11c1aecd2b1

1220222440113 has 8 divisors (see below), whose sum is σ = 1627532730528. Its totient is φ = 813196888224.

The previous prime is 1220222440109. The next prime is 1220222440127. The reversal of 1220222440113 is 3110442220221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1220222440113 - 22 = 1220222440109 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1220222420113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71174631 + ... + 71191772.

It is an arithmetic number, because the mean of its divisors is an integer number (203441591316).

Almost surely, 21220222440113 is an apocalyptic number.

It is an amenable number.

1220222440113 is a deficient number, since it is larger than the sum of its proper divisors (407310290415).

1220222440113 is a wasteful number, since it uses less digits than its factorization.

1220222440113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 142369263.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 1220222440113 its reverse (3110442220221), we get a palindrome (4330664660334).

The spelling of 1220222440113 in words is "one trillion, two hundred twenty billion, two hundred twenty-two million, four hundred forty thousand, one hundred thirteen".

Divisors: 1 3 2857 8571 142366403 427099209 406740813371 1220222440113