Base | Representation |
---|---|
bin | 10001110000011010111… |
… | …011001101001010110001 |
3 | 11022122121101210111200220 |
4 | 101300122323031022301 |
5 | 124443003421040423 |
6 | 2332321253403253 |
7 | 154105151415255 |
oct | 21603273151261 |
9 | 4278541714626 |
10 | 1220222440113 |
11 | 430547835716 |
12 | 1785a2039529 |
13 | 8b0b30a58c1 |
14 | 430b8194265 |
15 | 21b1a2449e3 |
hex | 11c1aecd2b1 |
1220222440113 has 8 divisors (see below), whose sum is σ = 1627532730528. Its totient is φ = 813196888224.
The previous prime is 1220222440109. The next prime is 1220222440127. The reversal of 1220222440113 is 3110442220221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1220222440113 - 22 = 1220222440109 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1220222420113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71174631 + ... + 71191772.
It is an arithmetic number, because the mean of its divisors is an integer number (203441591316).
Almost surely, 21220222440113 is an apocalyptic number.
It is an amenable number.
1220222440113 is a deficient number, since it is larger than the sum of its proper divisors (407310290415).
1220222440113 is a wasteful number, since it uses less digits than its factorization.
1220222440113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142369263.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 1220222440113 its reverse (3110442220221), we get a palindrome (4330664660334).
The spelling of 1220222440113 in words is "one trillion, two hundred twenty billion, two hundred twenty-two million, four hundred forty thousand, one hundred thirteen".
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