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1220231300113 = 7834172089727
BaseRepresentation
bin10001110000011011011…
…101000000010000010001
311022122122000110122100001
4101300123131000100101
5124443013203100423
62332322211330001
7154105316626210
oct21603335002021
94278560418301
101220231300113
11430551837331
121785a4bb0901
138b0b4b885c7
14430b941d077
1521b1ade4cad
hex11c1b740411

1220231300113 has 8 divisors (see below), whose sum is σ = 1394567442432. Its totient is φ = 1045899504096.

The previous prime is 1220231300087. The next prime is 1220231300117. The reversal of 1220231300113 is 3110031320221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1220231300113 - 213 = 1220231291921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1220231300117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 460945 + ... + 1628782.

It is an arithmetic number, because the mean of its divisors is an integer number (174320930304).

Almost surely, 21220231300113 is an apocalyptic number.

It is an amenable number.

1220231300113 is a deficient number, since it is larger than the sum of its proper divisors (174336142319).

1220231300113 is an equidigital number, since it uses as much as digits as its factorization.

1220231300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2173151.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1220231300113 its reverse (3110031320221), we get a palindrome (4330262620334).

The spelling of 1220231300113 in words is "one trillion, two hundred twenty billion, two hundred thirty-one million, three hundred thousand, one hundred thirteen".

Divisors: 1 7 83417 583919 2089727 14628089 174318757159 1220231300113