Base | Representation |
---|---|
bin | 111000110100110011… |
… | …1010100101001000011 |
3 | 102122222112212002220112 |
4 | 1301221213110221003 |
5 | 3444404414001011 |
6 | 132021003501535 |
7 | 11550020246405 |
oct | 1615147245103 |
9 | 378875762815 |
10 | 122031000131 |
11 | 47831355627 |
12 | 1b797b278ab |
13 | b679bc69b1 |
14 | 5c98d90b75 |
15 | 329343d58b |
hex | 1c699d4a43 |
122031000131 has 2 divisors, whose sum is σ = 122031000132. Its totient is φ = 122031000130.
The previous prime is 122031000127. The next prime is 122031000211. The reversal of 122031000131 is 131000130221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 122031000131 - 22 = 122031000127 is a prime.
It is a super-2 number, since 2×1220310001312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (122031000331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61015500065 + 61015500066.
It is an arithmetic number, because the mean of its divisors is an integer number (61015500066).
Almost surely, 2122031000131 is an apocalyptic number.
122031000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
122031000131 is an equidigital number, since it uses as much as digits as its factorization.
122031000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 122031000131 its reverse (131000130221), we get a palindrome (253031130352).
The spelling of 122031000131 in words is "one hundred twenty-two billion, thirty-one million, one hundred thirty-one", and thus it is an aban number.
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