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12203311414403 is a prime number
BaseRepresentation
bin1011000110010100111000…
…0010101011110010000011
31121012121212202101001212202
42301211032002223302003
53044414340210230103
641542042431143415
72366442301351634
oct261451602536203
947177782331782
1012203311414403
11398543917671a
121451100374b6b
136a69c8a89665
143029017ab88b
15162681e4e988
hexb194e0abc83

12203311414403 has 2 divisors, whose sum is σ = 12203311414404. Its totient is φ = 12203311414402.

The previous prime is 12203311414397. The next prime is 12203311414423. The reversal of 12203311414403 is 30441411330221.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12203311414403 is a prime.

It is not a weakly prime, because it can be changed into another prime (12203311414423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101655707201 + 6101655707202.

It is an arithmetic number, because the mean of its divisors is an integer number (6101655707202).

Almost surely, 212203311414403 is an apocalyptic number.

12203311414403 is a deficient number, since it is larger than the sum of its proper divisors (1).

12203311414403 is an equidigital number, since it uses as much as digits as its factorization.

12203311414403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 12203311414403 its reverse (30441411330221), we get a palindrome (42644722744624).

The spelling of 12203311414403 in words is "twelve trillion, two hundred three billion, three hundred eleven million, four hundred fourteen thousand, four hundred three".