Base | Representation |
---|---|
bin | 1011000110010100111000… |
… | …0010101011110010000011 |
3 | 1121012121212202101001212202 |
4 | 2301211032002223302003 |
5 | 3044414340210230103 |
6 | 41542042431143415 |
7 | 2366442301351634 |
oct | 261451602536203 |
9 | 47177782331782 |
10 | 12203311414403 |
11 | 398543917671a |
12 | 1451100374b6b |
13 | 6a69c8a89665 |
14 | 3029017ab88b |
15 | 162681e4e988 |
hex | b194e0abc83 |
12203311414403 has 2 divisors, whose sum is σ = 12203311414404. Its totient is φ = 12203311414402.
The previous prime is 12203311414397. The next prime is 12203311414423. The reversal of 12203311414403 is 30441411330221.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12203311414403 is a prime.
It is not a weakly prime, because it can be changed into another prime (12203311414423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101655707201 + 6101655707202.
It is an arithmetic number, because the mean of its divisors is an integer number (6101655707202).
Almost surely, 212203311414403 is an apocalyptic number.
12203311414403 is a deficient number, since it is larger than the sum of its proper divisors (1).
12203311414403 is an equidigital number, since it uses as much as digits as its factorization.
12203311414403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 12203311414403 its reverse (30441411330221), we get a palindrome (42644722744624).
The spelling of 12203311414403 in words is "twelve trillion, two hundred three billion, three hundred eleven million, four hundred fourteen thousand, four hundred three".
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