Base | Representation |
---|---|
bin | 111000110101100000… |
… | …1110111011001001001 |
3 | 102200001012111222121210 |
4 | 1301223001313121021 |
5 | 3444432003013213 |
6 | 132023212323333 |
7 | 11550426063501 |
oct | 1615301673111 |
9 | 380035458553 |
10 | 122054735433 |
11 | 47843797284 |
12 | 1b7a3a73549 |
13 | b681ab7357 |
14 | 5c9c1aca01 |
15 | 329557b0c3 |
hex | 1c6b077649 |
122054735433 has 16 divisors (see below), whose sum is σ = 163091690496. Its totient is φ = 81193915920.
The previous prime is 122054735381. The next prime is 122054735441. The reversal of 122054735433 is 334537450221.
It is a happy number.
It is a de Polignac number, because none of the positive numbers 2k-122054735433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 122054735391 and 122054735400.
It is not an unprimeable number, because it can be changed into a prime (122054735633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4863628 + ... + 4888658.
It is an arithmetic number, because the mean of its divisors is an integer number (10193230656).
Almost surely, 2122054735433 is an apocalyptic number.
It is an amenable number.
122054735433 is a deficient number, since it is larger than the sum of its proper divisors (41036955063).
122054735433 is a wasteful number, since it uses less digits than its factorization.
122054735433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28484.
The product of its (nonzero) digits is 302400, while the sum is 39.
The spelling of 122054735433 in words is "one hundred twenty-two billion, fifty-four million, seven hundred thirty-five thousand, four hundred thirty-three".
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