Base | Representation |
---|---|
bin | 10001110001001001000… |
… | …101101000100100000001 |
3 | 11022201121101010110012011 |
4 | 101301021011220210001 |
5 | 130001100203110242 |
6 | 2332530201332521 |
7 | 154133304424603 |
oct | 21611105504401 |
9 | 4281541113164 |
10 | 1220996925697 |
11 | 430904a2a14a |
12 | 178779497141 |
13 | 8b1a76943b3 |
14 | 4314cd9b173 |
15 | 21b6322bd17 |
hex | 11c49168901 |
1220996925697 has 2 divisors, whose sum is σ = 1220996925698. Its totient is φ = 1220996925696.
The previous prime is 1220996925683. The next prime is 1220996925713. The reversal of 1220996925697 is 7965296990221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1079928326416 + 141068599281 = 1039196^2 + 375591^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1220996925697 is a prime.
It is a super-3 number, since 3×12209969256973 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1220996325697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610498462848 + 610498462849.
It is an arithmetic number, because the mean of its divisors is an integer number (610498462849).
Almost surely, 21220996925697 is an apocalyptic number.
It is an amenable number.
1220996925697 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220996925697 is an equidigital number, since it uses as much as digits as its factorization.
1220996925697 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 66134880, while the sum is 67.
The spelling of 1220996925697 in words is "one trillion, two hundred twenty billion, nine hundred ninety-six million, nine hundred twenty-five thousand, six hundred ninety-seven".
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