Base | Representation |
---|---|
bin | 11011110000110010100101… |
… | …001001011101001011010011 |
3 | 121000022122200222100002000012 |
4 | 123300302211021131023103 |
5 | 112000442001324311011 |
6 | 1111404002333545135 |
7 | 34501304220221006 |
oct | 3360624511351323 |
9 | 530278628302005 |
10 | 122100101010131 |
11 | 359a53a8971542 |
12 | 1183b9989451ab |
13 | 5318cb43a8c8a |
14 | 222196815553d |
15 | e1b185671a8b |
hex | 6f0ca525d2d3 |
122100101010131 has 2 divisors, whose sum is σ = 122100101010132. Its totient is φ = 122100101010130.
The previous prime is 122100101010077. The next prime is 122100101010149. The reversal of 122100101010131 is 131010101001221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122100101010131 - 218 = 122100100747987 is a prime.
It is a super-2 number, since 2×1221001010101312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (122100101010331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61050050505065 + 61050050505066.
It is an arithmetic number, because the mean of its divisors is an integer number (61050050505066).
Almost surely, 2122100101010131 is an apocalyptic number.
122100101010131 is a deficient number, since it is larger than the sum of its proper divisors (1).
122100101010131 is an equidigital number, since it uses as much as digits as its factorization.
122100101010131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 122100101010131 its reverse (131010101001221), we get a palindrome (253110202011352).
The spelling of 122100101010131 in words is "one hundred twenty-two trillion, one hundred billion, one hundred one million, ten thousand, one hundred thirty-one".
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