Base | Representation |
---|---|
bin | 1011000110101101110110… |
… | …0100001010111111001001 |
3 | 1121020021011220001001021121 |
4 | 2301223131210022333021 |
5 | 3100022102130132103 |
6 | 41545111513235241 |
7 | 2400100352066503 |
oct | 261533544127711 |
9 | 47207156031247 |
10 | 12210014302153 |
11 | 3988268839478 |
12 | 1452471102b21 |
13 | 6a7526666025 |
14 | 302d79aa6d73 |
15 | 16292562a6bd |
hex | b1add90afc9 |
12210014302153 has 2 divisors, whose sum is σ = 12210014302154. Its totient is φ = 12210014302152.
The previous prime is 12210014302111. The next prime is 12210014302201. The reversal of 12210014302153 is 35120341001221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11948691929344 + 261322372809 = 3456688^2 + 511197^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12210014302153 is a prime.
It is not a weakly prime, because it can be changed into another prime (12210014302103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105007151076 + 6105007151077.
It is an arithmetic number, because the mean of its divisors is an integer number (6105007151077).
Almost surely, 212210014302153 is an apocalyptic number.
It is an amenable number.
12210014302153 is a deficient number, since it is larger than the sum of its proper divisors (1).
12210014302153 is an equidigital number, since it uses as much as digits as its factorization.
12210014302153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 12210014302153 its reverse (35120341001221), we get a palindrome (47330355303374).
The spelling of 12210014302153 in words is "twelve trillion, two hundred ten billion, fourteen million, three hundred two thousand, one hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •