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122102412240433 is a prime number
BaseRepresentation
bin11011110000110100101110…
…111010000110011000110001
3121000022212200001022201221111
4123300310232322012120301
5112001011220013143213
61111405023535353321
734501415413314532
oct3360645672063061
9530285601281844
10122102412240433
11359a6384563029
1211840322982841
135319292183981
142221b070a8689
15e1b26d510a3d
hex6f0d2ee86631

122102412240433 has 2 divisors, whose sum is σ = 122102412240434. Its totient is φ = 122102412240432.

The previous prime is 122102412240353. The next prime is 122102412240469. The reversal of 122102412240433 is 334042214201221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117268605457969 + 4833806782464 = 10829063^2 + 2198592^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122102412240433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 122102412240395 and 122102412240404.

It is not a weakly prime, because it can be changed into another prime (122102412240533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61051206120216 + 61051206120217.

It is an arithmetic number, because the mean of its divisors is an integer number (61051206120217).

Almost surely, 2122102412240433 is an apocalyptic number.

It is an amenable number.

122102412240433 is a deficient number, since it is larger than the sum of its proper divisors (1).

122102412240433 is an equidigital number, since it uses as much as digits as its factorization.

122102412240433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 122102412240433 its reverse (334042214201221), we get a palindrome (456144626441654).

The spelling of 122102412240433 in words is "one hundred twenty-two trillion, one hundred two billion, four hundred twelve million, two hundred forty thousand, four hundred thirty-three".