Base | Representation |
---|---|
bin | 10001110001001011001… |
… | …000001010011110011001 |
3 | 11022201200202111212221120 |
4 | 101301023020022132121 |
5 | 130001132433041241 |
6 | 2332533422555453 |
7 | 154134201320463 |
oct | 21611310123631 |
9 | 4281622455846 |
10 | 1221031143321 |
11 | 430922280380 |
12 | 178788a38b89 |
13 | 8b1b17b5002 |
14 | 43153747133 |
15 | 21b6623a666 |
hex | 11c4b20a799 |
1221031143321 has 32 divisors (see below), whose sum is σ = 1783397468160. Its totient is φ = 736957372800.
The previous prime is 1221031143289. The next prime is 1221031143331. The reversal of 1221031143321 is 1233411301221.
It is not a de Polignac number, because 1221031143321 - 25 = 1221031143289 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1221031143291 and 1221031143300.
It is not an unprimeable number, because it can be changed into a prime (1221031143331) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27672645 + ... + 27716733.
It is an arithmetic number, because the mean of its divisors is an integer number (55731170880).
Almost surely, 21221031143321 is an apocalyptic number.
1221031143321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1221031143321 is a deficient number, since it is larger than the sum of its proper divisors (562366324839).
1221031143321 is a wasteful number, since it uses less digits than its factorization.
1221031143321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47557.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 1221031143321 its reverse (1233411301221), we get a palindrome (2454442444542).
The spelling of 1221031143321 in words is "one trillion, two hundred twenty-one billion, thirty-one million, one hundred forty-three thousand, three hundred twenty-one".
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