Base | Representation |
---|---|
bin | 10001110001001011010… |
… | …100011001101000110011 |
3 | 11022201200222112212021020 |
4 | 101301023110121220303 |
5 | 130001134243214110 |
6 | 2332534015430523 |
7 | 154134240510663 |
oct | 21611324315063 |
9 | 4281628485236 |
10 | 1221034351155 |
11 | 430924071483 |
12 | 178789b25443 |
13 | 8b1b2369138 |
14 | 43153d401a3 |
15 | 21b66670d70 |
hex | 11c4b519a33 |
1221034351155 has 16 divisors (see below), whose sum is σ = 1954104285600. Its totient is φ = 651068546048.
The previous prime is 1221034351123. The next prime is 1221034351183. The reversal of 1221034351155 is 5511534301221.
It is a cyclic number.
It is not a de Polignac number, because 1221034351155 - 25 = 1221034351123 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9293502 + ... + 9423971.
It is an arithmetic number, because the mean of its divisors is an integer number (122131517850).
Almost surely, 21221034351155 is an apocalyptic number.
1221034351155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1221034351155 is a deficient number, since it is larger than the sum of its proper divisors (733069934445).
1221034351155 is a wasteful number, since it uses less digits than its factorization.
1221034351155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18721830.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 1221034351155 its reverse (5511534301221), we get a palindrome (6732568652376).
The spelling of 1221034351155 in words is "one trillion, two hundred twenty-one billion, thirty-four million, three hundred fifty-one thousand, one hundred fifty-five".
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