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12210433113 = 313729709083
BaseRepresentation
bin10110101111100110…
…00110110001011001
31011111222002021022110
423113303012301121
5200001332324423
65335343542533
7611404653234
oct132763066131
934458067273
1012210433113
1151a652013a
1224492baa49
1311c7932868
1483b95841b
154b6e8b193
hex2d7cc6c59

12210433113 has 8 divisors (see below), whose sum is σ = 16399414368. Its totient is φ = 8080870304.

The previous prime is 12210433099. The next prime is 12210433117. The reversal of 12210433113 is 31133401221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12210433113 - 29 = 12210432601 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12210433113.

It is not an unprimeable number, because it can be changed into a prime (12210433117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14854131 + ... + 14854952.

It is an arithmetic number, because the mean of its divisors is an integer number (2049926796).

Almost surely, 212210433113 is an apocalyptic number.

It is an amenable number.

12210433113 is a deficient number, since it is larger than the sum of its proper divisors (4188981255).

12210433113 is a wasteful number, since it uses less digits than its factorization.

12210433113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29709223.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 12210433113 its reverse (31133401221), we get a palindrome (43343834334).

The spelling of 12210433113 in words is "twelve billion, two hundred ten million, four hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 3 137 411 29709083 89127249 4070144371 12210433113