Base | Representation |
---|---|
bin | 10001110001001111010… |
… | …011110011100011100001 |
3 | 11022201212122112102100110 |
4 | 101301033103303203201 |
5 | 130001303413212113 |
6 | 2332544410441533 |
7 | 154136012553612 |
oct | 21611723634341 |
9 | 4281778472313 |
10 | 1221101304033 |
11 | 430958941136 |
12 | 1787a84332a9 |
13 | 8b1c31aba20 |
14 | 4315cbabc09 |
15 | 21b6c498bc3 |
hex | 11c4f4f38e1 |
1221101304033 has 16 divisors (see below), whose sum is σ = 1753414790400. Its totient is φ = 751430431104.
The previous prime is 1221101303969. The next prime is 1221101304151. The reversal of 1221101304033 is 3304031011221.
It is not a de Polignac number, because 1221101304033 - 26 = 1221101303969 is a prime.
It is a super-2 number, since 2×12211013040332 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1221101304233) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1589368 + ... + 2228966.
It is an arithmetic number, because the mean of its divisors is an integer number (109588424400).
Almost surely, 21221101304033 is an apocalyptic number.
1221101304033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1221101304033 is a deficient number, since it is larger than the sum of its proper divisors (532313486367).
1221101304033 is a wasteful number, since it uses less digits than its factorization.
1221101304033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 688568.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1221101304033 its reverse (3304031011221), we get a palindrome (4525132315254).
The spelling of 1221101304033 in words is "one trillion, two hundred twenty-one billion, one hundred one million, three hundred four thousand, thirty-three".
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