Base | Representation |
---|---|
bin | 1011000110110001100110… |
… | …0000101001100111101011 |
3 | 1121020100202222110101211212 |
4 | 2301230121200221213223 |
5 | 3100031132110341021 |
6 | 41545355401143335 |
7 | 2400134313351302 |
oct | 261543140514753 |
9 | 47210688411755 |
10 | 12211020012011 |
11 | 3988734502147 |
12 | 14526b1a8ab4b |
13 | 6a7656b22112 |
14 | 30303349d439 |
15 | 162983a8885b |
hex | b1b198299eb |
12211020012011 has 2 divisors, whose sum is σ = 12211020012012. Its totient is φ = 12211020012010.
The previous prime is 12211020011989. The next prime is 12211020012017. The reversal of 12211020012011 is 11021002011221.
12211020012011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (11021002011221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12211020012011 - 230 = 12209946270187 is a prime.
It is not a weakly prime, because it can be changed into another prime (12211020012017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105510006005 + 6105510006006.
It is an arithmetic number, because the mean of its divisors is an integer number (6105510006006).
Almost surely, 212211020012011 is an apocalyptic number.
12211020012011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211020012011 is an equidigital number, since it uses as much as digits as its factorization.
12211020012011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 12211020012011 its reverse (11021002011221), we get a palindrome (23232022023232).
The spelling of 12211020012011 in words is "twelve trillion, two hundred eleven billion, twenty million, twelve thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •