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12211111102147 is a prime number
BaseRepresentation
bin1011000110110001111011…
…1100001000011011000011
31121020101000022212021000121
42301230132330020123003
53100031323420232042
641545412413401111
72400136500534226
oct261543674103303
947211008767017
1012211111102147
113988780968551
121452718499197
136a766c9662c9
143030416115bd
1516298ba7d367
hexb1b1ef086c3

12211111102147 has 2 divisors, whose sum is σ = 12211111102148. Its totient is φ = 12211111102146.

The previous prime is 12211111101997. The next prime is 12211111102181. The reversal of 12211111102147 is 74120111111221.

12211111102147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12211111102147 - 231 = 12208963618499 is a prime.

It is a super-2 number, since 2×122111111021472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12211111106147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105555551073 + 6105555551074.

It is an arithmetic number, because the mean of its divisors is an integer number (6105555551074).

Almost surely, 212211111102147 is an apocalyptic number.

12211111102147 is a deficient number, since it is larger than the sum of its proper divisors (1).

12211111102147 is an equidigital number, since it uses as much as digits as its factorization.

12211111102147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 224, while the sum is 25.

Adding to 12211111102147 its reverse (74120111111221), we get a palindrome (86331222213368).

The spelling of 12211111102147 in words is "twelve trillion, two hundred eleven billion, one hundred eleven million, one hundred two thousand, one hundred forty-seven".