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1221112040353 is a prime number
BaseRepresentation
bin10001110001001111111…
…100110000101110100001
311022201220101201212210221
4101301033330300232201
5130001314140242403
62332545432523041
7154136203041052
oct21611774605641
94281811655727
101221112040353
11430963a04527
121787abb50481
138b1c549a78a
14431603a4729
1521b6d3b9dbd
hex11c4ff30ba1

1221112040353 has 2 divisors, whose sum is σ = 1221112040354. Its totient is φ = 1221112040352.

The previous prime is 1221112040339. The next prime is 1221112040359. The reversal of 1221112040353 is 3530402111221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1158708003489 + 62404036864 = 1076433^2 + 249808^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1221112040353 is a prime.

It is a super-2 number, since 2×12211120403532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1221112040359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610556020176 + 610556020177.

It is an arithmetic number, because the mean of its divisors is an integer number (610556020177).

Almost surely, 21221112040353 is an apocalyptic number.

It is an amenable number.

1221112040353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1221112040353 is an equidigital number, since it uses as much as digits as its factorization.

1221112040353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1221112040353 its reverse (3530402111221), we get a palindrome (4751514151574).

The spelling of 1221112040353 in words is "one trillion, two hundred twenty-one billion, one hundred twelve million, forty thousand, three hundred fifty-three".