Base | Representation |
---|---|
bin | 1011000110110010011000… |
… | …1010100101011000100011 |
3 | 1121020101022202222100011012 |
4 | 2301230212022211120203 |
5 | 3100032100434100144 |
6 | 41545432424011135 |
7 | 2400142502135051 |
oct | 261544612453043 |
9 | 47211282870135 |
10 | 12211232331299 |
11 | 3988833339831 |
12 | 1452751000aab |
13 | 6a768bb00831 |
14 | 30305376b1d1 |
15 | 162997527e9e |
hex | b1b262a5623 |
12211232331299 has 2 divisors, whose sum is σ = 12211232331300. Its totient is φ = 12211232331298.
The previous prime is 12211232331169. The next prime is 12211232331323. The reversal of 12211232331299 is 99213323211221.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12211232331299 is a prime.
It is a super-4 number, since 4×122112323312994 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (12211232336299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105616165649 + 6105616165650.
It is an arithmetic number, because the mean of its divisors is an integer number (6105616165650).
Almost surely, 212211232331299 is an apocalyptic number.
12211232331299 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211232331299 is an equidigital number, since it uses as much as digits as its factorization.
12211232331299 is an evil number, because the sum of its binary digits is even.
The product of its digits is 69984, while the sum is 41.
The spelling of 12211232331299 in words is "twelve trillion, two hundred eleven billion, two hundred thirty-two million, three hundred thirty-one thousand, two hundred ninety-nine".
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