Base | Representation |
---|---|
bin | 10001110001010000101… |
… | …011100011001000101011 |
3 | 11022201221020211000100211 |
4 | 101301100223203020223 |
5 | 130001330310233301 |
6 | 2332550551441551 |
7 | 154136412223261 |
oct | 21612053431053 |
9 | 4281836730324 |
10 | 1221124305451 |
11 | 43096a921476 |
12 | 1787b40862b7 |
13 | 8b1c7ba332b |
14 | 43161c78431 |
15 | 21b6e4de051 |
hex | 11c50ae322b |
1221124305451 has 2 divisors, whose sum is σ = 1221124305452. Its totient is φ = 1221124305450.
The previous prime is 1221124305433. The next prime is 1221124305503. The reversal of 1221124305451 is 1545034211221.
It is a weak prime.
It is an emirp because it is prime and its reverse (1545034211221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1221124305451 - 25 = 1221124305419 is a prime.
It is a super-2 number, since 2×12211243054512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1221124305421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610562152725 + 610562152726.
It is an arithmetic number, because the mean of its divisors is an integer number (610562152726).
Almost surely, 21221124305451 is an apocalyptic number.
1221124305451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221124305451 is an equidigital number, since it uses as much as digits as its factorization.
1221124305451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 1221124305451 its reverse (1545034211221), we get a palindrome (2766158516672).
The spelling of 1221124305451 in words is "one trillion, two hundred twenty-one billion, one hundred twenty-four million, three hundred five thousand, four hundred fifty-one".
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