Base | Representation |
---|---|
bin | 10110101111101100… |
… | …11111010101001011 |
3 | 1011112000202100002021 |
4 | 23113312133111023 |
5 | 200002044221024 |
6 | 5335414545311 |
7 | 611415336304 |
oct | 132766372513 |
9 | 34460670067 |
10 | 12211320139 |
11 | 51a6a76617 |
12 | 2449668237 |
13 | 11c7b83525 |
14 | 83bb097ab |
15 | 4b70b3de4 |
hex | 2d7d9f54b |
12211320139 has 2 divisors, whose sum is σ = 12211320140. Its totient is φ = 12211320138.
The previous prime is 12211320101. The next prime is 12211320161. The reversal of 12211320139 is 93102311221.
It is a strong prime.
It is an emirp because it is prime and its reverse (93102311221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12211320139 - 213 = 12211311947 is a prime.
It is not a weakly prime, because it can be changed into another prime (12211320169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6105660069 + 6105660070.
It is an arithmetic number, because the mean of its divisors is an integer number (6105660070).
Almost surely, 212211320139 is an apocalyptic number.
12211320139 is a deficient number, since it is larger than the sum of its proper divisors (1).
12211320139 is an equidigital number, since it uses as much as digits as its factorization.
12211320139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 12211320139 in words is "twelve billion, two hundred eleven million, three hundred twenty thousand, one hundred thirty-nine".
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