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12212100113 = 15803772771
BaseRepresentation
bin10110101111110010…
…11101110000010001
31011112002012222000012
423113321131300101
5200002244200423
65335443404305
7611425065263
oct132771356021
934462188005
1012212100113
1151a7459624
122449983695
1311c8097555
1483bc6db33
154b71ba078
hex2d7e5dc11

12212100113 has 4 divisors (see below), whose sum is σ = 12212888688. Its totient is φ = 12211311540.

The previous prime is 12212100097. The next prime is 12212100149. The reversal of 12212100113 is 31100121221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12212100113 - 24 = 12212100097 is a prime.

It is a super-2 number, since 2×122121001132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12212100613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 370583 + ... + 402188.

It is an arithmetic number, because the mean of its divisors is an integer number (3053222172).

Almost surely, 212212100113 is an apocalyptic number.

It is an amenable number.

12212100113 is a deficient number, since it is larger than the sum of its proper divisors (788575).

12212100113 is an equidigital number, since it uses as much as digits as its factorization.

12212100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 788574.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 12212100113 its reverse (31100121221), we get a palindrome (43312221334).

The spelling of 12212100113 in words is "twelve billion, two hundred twelve million, one hundred thousand, one hundred thirteen".

Divisors: 1 15803 772771 12212100113