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12212132113 = 73167289481
BaseRepresentation
bin10110101111110011…
…00101100100010001
31011112002021120220101
423113321211210101
5200002301211423
65335444212401
7611425260466
oct132771454421
934462246811
1012212132113
1151a7480675
12244999a101
1311c80a8c9c
1483bc7b66d
154b71c47ad
hex2d7e65911

12212132113 has 4 divisors (see below), whose sum is σ = 12379421668. Its totient is φ = 12044842560.

The previous prime is 12212132089. The next prime is 12212132123. The reversal of 12212132113 is 31123121221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8996901904 + 3215230209 = 94852^2 + 56703^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12212132113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12212132123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83644668 + ... + 83644813.

It is an arithmetic number, because the mean of its divisors is an integer number (3094855417).

Almost surely, 212212132113 is an apocalyptic number.

It is an amenable number.

12212132113 is a deficient number, since it is larger than the sum of its proper divisors (167289555).

12212132113 is an equidigital number, since it uses as much as digits as its factorization.

12212132113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 167289554.

The product of its digits is 144, while the sum is 19.

Adding to 12212132113 its reverse (31123121221), we get a palindrome (43335253334).

The spelling of 12212132113 in words is "twelve billion, two hundred twelve million, one hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 73 167289481 12212132113