Base | Representation |
---|---|
bin | 1011000110110101111111… |
… | …1101100100111001100011 |
3 | 1121020110211100120121111201 |
4 | 2301231133331210321203 |
5 | 3100041042202444341 |
6 | 41550112543222031 |
7 | 2400205515160321 |
oct | 261553775447143 |
9 | 47213740517451 |
10 | 12212201999971 |
11 | 39891907261a6 |
12 | 14529818a7917 |
13 | 6a77b497ac8c |
14 | 303106460d11 |
15 | 162a02717331 |
hex | b1b5ff64e63 |
12212201999971 has 2 divisors, whose sum is σ = 12212201999972. Its totient is φ = 12212201999970.
The previous prime is 12212201999911. The next prime is 12212202000059. The reversal of 12212201999971 is 17999910221221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12212201999971 - 213 = 12212201991779 is a prime.
It is not a weakly prime, because it can be changed into another prime (12212201999911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106100999985 + 6106100999986.
It is an arithmetic number, because the mean of its divisors is an integer number (6106100999986).
Almost surely, 212212201999971 is an apocalyptic number.
12212201999971 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212201999971 is an equidigital number, since it uses as much as digits as its factorization.
12212201999971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 734832, while the sum is 55.
The spelling of 12212201999971 in words is "twelve trillion, two hundred twelve billion, two hundred one million, nine hundred ninety-nine thousand, nine hundred seventy-one".
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