Base | Representation |
---|---|
bin | 1011000110110101111111… |
… | …1110010101111110100001 |
3 | 1121020110211100221211020222 |
4 | 2301231133332111332201 |
5 | 3100041042230412433 |
6 | 41550112551412425 |
7 | 2400205516655354 |
oct | 261553776257641 |
9 | 47213740854228 |
10 | 12212202200993 |
11 | 3989190853233 |
12 | 1452981984115 |
13 | 6a77b4a1b622 |
14 | 3031064b429b |
15 | 162a02756b98 |
hex | b1b5ff95fa1 |
12212202200993 has 2 divisors, whose sum is σ = 12212202200994. Its totient is φ = 12212202200992.
The previous prime is 12212202200969. The next prime is 12212202201041. The reversal of 12212202200993 is 39900220221221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9362088421009 + 2850113779984 = 3059753^2 + 1688228^2 .
It is an emirp because it is prime and its reverse (39900220221221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12212202200993 - 216 = 12212202135457 is a prime.
It is a super-3 number, since 3×122122022009933 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12212202200923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106101100496 + 6106101100497.
It is an arithmetic number, because the mean of its divisors is an integer number (6106101100497).
Almost surely, 212212202200993 is an apocalyptic number.
It is an amenable number.
12212202200993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12212202200993 is an equidigital number, since it uses as much as digits as its factorization.
12212202200993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 12212202200993 in words is "twelve trillion, two hundred twelve billion, two hundred two million, two hundred thousand, nine hundred ninety-three".
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