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12212233113 = 34070744371
BaseRepresentation
bin10110101111110011…
…11110001110011001
31011112002110201110010
423113321332032121
5200002312424423
65335450312133
7611426161113
oct132771761631
934462421403
1012212233113
1151a753a543
122449a28649
1311c8112c52
1483bca63b3
154b71e4693
hex2d7e7e399

12212233113 has 4 divisors (see below), whose sum is σ = 16282977488. Its totient is φ = 8141488740.

The previous prime is 12212233069. The next prime is 12212233133. The reversal of 12212233113 is 31133221221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12212233113 - 214 = 12212216729 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12212233113.

It is not an unprimeable number, because it can be changed into a prime (12212233133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2035372183 + ... + 2035372188.

It is an arithmetic number, because the mean of its divisors is an integer number (4070744372).

Almost surely, 212212233113 is an apocalyptic number.

It is an amenable number.

12212233113 is a deficient number, since it is larger than the sum of its proper divisors (4070744375).

12212233113 is an equidigital number, since it uses as much as digits as its factorization.

12212233113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4070744374.

The product of its digits is 432, while the sum is 21.

Adding to 12212233113 its reverse (31133221221), we get a palindrome (43345454334).

The spelling of 12212233113 in words is "twelve billion, two hundred twelve million, two hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 3 4070744371 12212233113