Base | Representation |
---|---|
bin | 1011000110110110011100… |
… | …0100000001011000010011 |
3 | 1121020111010122202001012010 |
4 | 2301231213010001120103 |
5 | 3100041313202130003 |
6 | 41550132440434003 |
7 | 2400211462566231 |
oct | 261554704013023 |
9 | 47214118661163 |
10 | 12212321130003 |
11 | 39892419a3375 |
12 | 14529b5778903 |
13 | 6a780355bc17 |
14 | 3031181d1951 |
15 | 162a0cdea003 |
hex | b1b67101613 |
12212321130003 has 4 divisors (see below), whose sum is σ = 16283094840008. Its totient is φ = 8141547420000.
The previous prime is 12212321130001. The next prime is 12212321130007. The reversal of 12212321130003 is 30003112321221.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 12212321130003 - 21 = 12212321130001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12212321130001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2035386854998 + ... + 2035386855003.
It is an arithmetic number, because the mean of its divisors is an integer number (4070773710002).
Almost surely, 212212321130003 is an apocalyptic number.
12212321130003 is a deficient number, since it is larger than the sum of its proper divisors (4070773710005).
12212321130003 is an equidigital number, since it uses as much as digits as its factorization.
12212321130003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4070773710004.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 12212321130003 its reverse (30003112321221), we get a palindrome (42215433451224).
The spelling of 12212321130003 in words is "twelve trillion, two hundred twelve billion, three hundred twenty-one million, one hundred thirty thousand, three".
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