Base | Representation |
---|---|
bin | 11011110001001110101000… |
… | …011111111101011101111011 |
3 | 121000102112110011022112010111 |
4 | 123301032220133331131323 |
5 | 112001440143313343113 |
6 | 1111425503251325151 |
7 | 34503421516423552 |
oct | 3361165037753573 |
9 | 530375404275114 |
10 | 122130222012283 |
11 | 35a07155441251 |
12 | 118457a42b07b7 |
13 | 531baa4859184 |
14 | 22231c469ad99 |
15 | e1bd49bed13d |
hex | 6f13a87fd77b |
122130222012283 has 2 divisors, whose sum is σ = 122130222012284. Its totient is φ = 122130222012282.
The previous prime is 122130222012241. The next prime is 122130222012311. The reversal of 122130222012283 is 382210222031221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122130222012283 - 217 = 122130221881211 is a prime.
It is a super-2 number, since 2×1221302220122832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (122130222012983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61065111006141 + 61065111006142.
It is an arithmetic number, because the mean of its divisors is an integer number (61065111006142).
Almost surely, 2122130222012283 is an apocalyptic number.
122130222012283 is a deficient number, since it is larger than the sum of its proper divisors (1).
122130222012283 is an equidigital number, since it uses as much as digits as its factorization.
122130222012283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 31.
The spelling of 122130222012283 in words is "one hundred twenty-two trillion, one hundred thirty billion, two hundred twenty-two million, twelve thousand, two hundred eighty-three".
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