Base | Representation |
---|---|
bin | 1011000110111001011010… |
… | …1111011001111101001011 |
3 | 1121020120012101220021110102 |
4 | 2301232112233121331023 |
5 | 3100044432441011021 |
6 | 41550344053240015 |
7 | 2400240344624114 |
oct | 261562657317513 |
9 | 47216171807412 |
10 | 12213121032011 |
11 | 3989612477609 |
12 | 1452b9963300b |
13 | 6a79001a9313 |
14 | 30319253320b |
15 | 162a5825300b |
hex | b1b96bd9f4b |
12213121032011 has 4 divisors (see below), whose sum is σ = 12443557277952. Its totient is φ = 11982684786072.
The previous prime is 12213121031977. The next prime is 12213121032023. The reversal of 12213121032011 is 11023012131221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12213121032011 - 242 = 7815074520907 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12213121031011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115218122891 + ... + 115218122996.
It is an arithmetic number, because the mean of its divisors is an integer number (3110889319488).
Almost surely, 212213121032011 is an apocalyptic number.
12213121032011 is a deficient number, since it is larger than the sum of its proper divisors (230436245941).
12213121032011 is an equidigital number, since it uses as much as digits as its factorization.
12213121032011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 230436245940.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 12213121032011 its reverse (11023012131221), we get a palindrome (23236133163232).
The spelling of 12213121032011 in words is "twelve trillion, two hundred thirteen billion, one hundred twenty-one million, thirty-two thousand, eleven".
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