Base | Representation |
---|---|
bin | 1011000110111001011101… |
… | …0101110100000001001001 |
3 | 1121020120020002211210110112 |
4 | 2301232113111310001021 |
5 | 3100044443030201413 |
6 | 41550345053124105 |
7 | 2400240526326410 |
oct | 261562725640111 |
9 | 47216202753415 |
10 | 12213131100233 |
11 | 3989618123a58 |
12 | 1452ba0a89635 |
13 | 6a79022c2c4b |
14 | 3031939d4477 |
15 | 162a590912a8 |
hex | b1b97574049 |
12213131100233 has 16 divisors (see below), whose sum is σ = 14026455907200. Its totient is φ = 10417079264256.
The previous prime is 12213131100217. The next prime is 12213131100277. The reversal of 12213131100233 is 33200113131221.
It is not a de Polignac number, because 12213131100233 - 24 = 12213131100217 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12213131100199 and 12213131100208.
It is not an unprimeable number, because it can be changed into a prime (12213131100283) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4036535 + ... + 6381212.
It is an arithmetic number, because the mean of its divisors is an integer number (876653494200).
Almost surely, 212213131100233 is an apocalyptic number.
It is an amenable number.
12213131100233 is a deficient number, since it is larger than the sum of its proper divisors (1813324806967).
12213131100233 is a wasteful number, since it uses less digits than its factorization.
12213131100233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10418576.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12213131100233 its reverse (33200113131221), we get a palindrome (45413244231454).
The spelling of 12213131100233 in words is "twelve trillion, two hundred thirteen billion, one hundred thirty-one million, one hundred thousand, two hundred thirty-three".
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