Base | Representation |
---|---|
bin | 1011000110111001101110… |
… | …1000100010111111110001 |
3 | 1121020120102010100210011111 |
4 | 2301232123220202333301 |
5 | 3100100114444320423 |
6 | 41550400144513321 |
7 | 2400242362435042 |
oct | 261563350427761 |
9 | 47216363323144 |
10 | 12213203120113 |
11 | 3989654844616 |
12 | 145300101b841 |
13 | 6a79141bac68 |
14 | 30319d3c08c9 |
15 | 162a6056a60d |
hex | b1b9ba22ff1 |
12213203120113 has 2 divisors, whose sum is σ = 12213203120114. Its totient is φ = 12213203120112.
The previous prime is 12213203120093. The next prime is 12213203120117. The reversal of 12213203120113 is 31102130231221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7303225192704 + 4909977927409 = 2702448^2 + 2215847^2 .
It is a cyclic number.
It is not a de Polignac number, because 12213203120113 - 221 = 12213201022961 is a prime.
It is not a weakly prime, because it can be changed into another prime (12213203120117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106601560056 + 6106601560057.
It is an arithmetic number, because the mean of its divisors is an integer number (6106601560057).
Almost surely, 212213203120113 is an apocalyptic number.
It is an amenable number.
12213203120113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213203120113 is an equidigital number, since it uses as much as digits as its factorization.
12213203120113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 12213203120113 its reverse (31102130231221), we get a palindrome (43315333351334).
The spelling of 12213203120113 in words is "twelve trillion, two hundred thirteen billion, two hundred three million, one hundred twenty thousand, one hundred thirteen".
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