Base | Representation |
---|---|
bin | 1011000110111001110000… |
… | …1010110110100010011001 |
3 | 1121020120102202021200011012 |
4 | 2301232130022312202121 |
5 | 3100100124300104144 |
6 | 41550401105343305 |
7 | 2400242532041363 |
oct | 261563412664231 |
9 | 47216382250135 |
10 | 12213212113049 |
11 | 39896599270a2 |
12 | 1453004037b35 |
13 | 6a791601931c |
14 | 3031a0681d33 |
15 | 162a61244e9e |
hex | b1b9c2b6899 |
12213212113049 has 2 divisors, whose sum is σ = 12213212113050. Its totient is φ = 12213212113048.
The previous prime is 12213212112989. The next prime is 12213212113057. The reversal of 12213212113049 is 94031121231221.
12213212113049 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11515163560000 + 698048553049 = 3393400^2 + 835493^2 .
It is a cyclic number.
It is not a de Polignac number, because 12213212113049 - 220 = 12213211064473 is a prime.
It is not a weakly prime, because it can be changed into another prime (12213212113549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106606056524 + 6106606056525.
It is an arithmetic number, because the mean of its divisors is an integer number (6106606056525).
Almost surely, 212213212113049 is an apocalyptic number.
It is an amenable number.
12213212113049 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213212113049 is an equidigital number, since it uses as much as digits as its factorization.
12213212113049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 32.
The spelling of 12213212113049 in words is "twelve trillion, two hundred thirteen billion, two hundred twelve million, one hundred thirteen thousand, forty-nine".
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