Base | Representation |
---|---|
bin | 1011000110111010001000… |
… | …0100110110000000010101 |
3 | 1121020120200122201212200110 |
4 | 2301232202010312000111 |
5 | 3100100330131420201 |
6 | 41550415005233233 |
7 | 2400245144215410 |
oct | 261564204660025 |
9 | 47216618655613 |
10 | 12213311201301 |
11 | 39896aa855611 |
12 | 1453031262819 |
13 | 6a7930700b22 |
14 | 3031ad8b6b77 |
15 | 162a69cb96d6 |
hex | b1ba2136015 |
12213311201301 has 16 divisors (see below), whose sum is σ = 18610843011200. Its totient is φ = 6979003815168.
The previous prime is 12213311201291. The next prime is 12213311201309. The reversal of 12213311201301 is 10310211331221.
It is not a de Polignac number, because 12213311201301 - 29 = 12213311200789 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12213311201309) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4025385 + ... + 6374193.
It is an arithmetic number, because the mean of its divisors is an integer number (1163177688200).
Almost surely, 212213311201301 is an apocalyptic number.
It is an amenable number.
12213311201301 is a deficient number, since it is larger than the sum of its proper divisors (6397531809899).
12213311201301 is a wasteful number, since it uses less digits than its factorization.
12213311201301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2596428.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 12213311201301 its reverse (10310211331221), we get a palindrome (22523522532522).
The spelling of 12213311201301 in words is "twelve trillion, two hundred thirteen billion, three hundred eleven million, two hundred one thousand, three hundred one".
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