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122133113132033 is a prime number
BaseRepresentation
bin11011110001010001010100…
…110100101101010000000001
3121000102210220122110121211202
4123301101110310231100001
5112002012103430211113
61111431102210150545
734503553253510243
oct3361212464552001
9530383818417752
10122133113132033
1135a083a93a5313
1211846270582455
13531c14580ac13
1422233ba640093
15e1be68936258
hex6f1454d2d401

122133113132033 has 2 divisors, whose sum is σ = 122133113132034. Its totient is φ = 122133113132032.

The previous prime is 122133113131969. The next prime is 122133113132053. The reversal of 122133113132033 is 330231311331221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66410650428529 + 55722462703504 = 8149273^2 + 7464748^2 .

It is a cyclic number.

It is not a de Polignac number, because 122133113132033 - 26 = 122133113131969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 122133113131987 and 122133113132005.

It is not a weakly prime, because it can be changed into another prime (122133113132053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61066556566016 + 61066556566017.

It is an arithmetic number, because the mean of its divisors is an integer number (61066556566017).

Almost surely, 2122133113132033 is an apocalyptic number.

It is an amenable number.

122133113132033 is a deficient number, since it is larger than the sum of its proper divisors (1).

122133113132033 is an equidigital number, since it uses as much as digits as its factorization.

122133113132033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 29.

Adding to 122133113132033 its reverse (330231311331221), we get a palindrome (452364424463254).

The spelling of 122133113132033 in words is "one hundred twenty-two trillion, one hundred thirty-three billion, one hundred thirteen million, one hundred thirty-two thousand, thirty-three".