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12213312131131 = 17928168123851
BaseRepresentation
bin1011000110111010001000…
…1000011001000000111011
31121020120200201111010011121
42301232202020121000323
53100100330401144011
641550415041210111
72400245155140316
oct261564210310073
947216621433147
1012213312131131
113989700330171
121453031630937
136a7930968117
143031ada7997d
15162a69deee71
hexb1ba221903b

12213312131131 has 4 divisors (see below), whose sum is σ = 12213380434264. Its totient is φ = 12213243828000.

The previous prime is 12213312131113. The next prime is 12213312131149. The reversal of 12213312131131 is 13113121331221.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (12213312131113) and next prime (12213312131149).

It is a cyclic number.

It is not a de Polignac number, because 12213312131131 - 239 = 11663556317243 is a prime.

It is a super-2 number, since 2×122133121311312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12213312131096 and 12213312131105.

It is not an unprimeable number, because it can be changed into a prime (12213312131101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33882645 + ... + 34241206.

It is an arithmetic number, because the mean of its divisors is an integer number (3053345108566).

Almost surely, 212213312131131 is an apocalyptic number.

12213312131131 is a deficient number, since it is larger than the sum of its proper divisors (68303133).

12213312131131 is an equidigital number, since it uses as much as digits as its factorization.

12213312131131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68303132.

The product of its digits is 648, while the sum is 25.

Adding to 12213312131131 its reverse (13113121331221), we get a palindrome (25326433462352).

The spelling of 12213312131131 in words is "twelve trillion, two hundred thirteen billion, three hundred twelve million, one hundred thirty-one thousand, one hundred thirty-one".

Divisors: 1 179281 68123851 12213312131131