Base | Representation |
---|---|
bin | 1011000110111010001000… |
… | …1000011001000000111011 |
3 | 1121020120200201111010011121 |
4 | 2301232202020121000323 |
5 | 3100100330401144011 |
6 | 41550415041210111 |
7 | 2400245155140316 |
oct | 261564210310073 |
9 | 47216621433147 |
10 | 12213312131131 |
11 | 3989700330171 |
12 | 1453031630937 |
13 | 6a7930968117 |
14 | 3031ada7997d |
15 | 162a69deee71 |
hex | b1ba221903b |
12213312131131 has 4 divisors (see below), whose sum is σ = 12213380434264. Its totient is φ = 12213243828000.
The previous prime is 12213312131113. The next prime is 12213312131149. The reversal of 12213312131131 is 13113121331221.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (12213312131113) and next prime (12213312131149).
It is a cyclic number.
It is not a de Polignac number, because 12213312131131 - 239 = 11663556317243 is a prime.
It is a super-2 number, since 2×122133121311312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12213312131096 and 12213312131105.
It is not an unprimeable number, because it can be changed into a prime (12213312131101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33882645 + ... + 34241206.
It is an arithmetic number, because the mean of its divisors is an integer number (3053345108566).
Almost surely, 212213312131131 is an apocalyptic number.
12213312131131 is a deficient number, since it is larger than the sum of its proper divisors (68303133).
12213312131131 is an equidigital number, since it uses as much as digits as its factorization.
12213312131131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 68303132.
The product of its digits is 648, while the sum is 25.
Adding to 12213312131131 its reverse (13113121331221), we get a palindrome (25326433462352).
The spelling of 12213312131131 in words is "twelve trillion, two hundred thirteen billion, three hundred twelve million, one hundred thirty-one thousand, one hundred thirty-one".
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