Base | Representation |
---|---|
bin | 11011110001010001011011… |
… | …110010100110011000011011 |
3 | 121000102211012210102011011021 |
4 | 123301101123302212120123 |
5 | 112002012323341120443 |
6 | 1111431121543343311 |
7 | 34503556203160660 |
oct | 3361213362463033 |
9 | 530384183364137 |
10 | 122133230020123 |
11 | 35a08459381043 |
12 | 118462a3751b37 |
13 | 531c163ab557a |
14 | 22233cbd89a67 |
15 | e1be73d249ed |
hex | 6f145bca661b |
122133230020123 has 4 divisors (see below), whose sum is σ = 139580834308720. Its totient is φ = 104685625731528.
The previous prime is 122133230020073. The next prime is 122133230020133. The reversal of 122133230020123 is 321020032331221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 122133230020123 - 233 = 122124640085531 is a prime.
It is not an unprimeable number, because it can be changed into a prime (122133230020133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8723802144288 + ... + 8723802144301.
It is an arithmetic number, because the mean of its divisors is an integer number (34895208577180).
Almost surely, 2122133230020123 is an apocalyptic number.
122133230020123 is a deficient number, since it is larger than the sum of its proper divisors (17447604288597).
122133230020123 is an equidigital number, since it uses as much as digits as its factorization.
122133230020123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17447604288596.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 122133230020123 its reverse (321020032331221), we get a palindrome (443153262351344).
The spelling of 122133230020123 in words is "one hundred twenty-two trillion, one hundred thirty-three billion, two hundred thirty million, twenty thousand, one hundred twenty-three".
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