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12213333013177 is a prime number
BaseRepresentation
bin1011000110111010001101…
…1000000011001010111001
31121020120202011210000221201
42301232203120003022321
53100100401222410202
641550421104534201
72400245530502032
oct261564330031271
947216664700851
1012213333013177
1139897110a315a
121453038621361
136a7935099b6a
143031b2753a89
15162a6bb77387
hexb1ba36032b9

12213333013177 has 2 divisors, whose sum is σ = 12213333013178. Its totient is φ = 12213333013176.

The previous prime is 12213333013157. The next prime is 12213333013213. The reversal of 12213333013177 is 77131033331221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11689314833296 + 524018179881 = 3418964^2 + 723891^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12213333013177 is a prime.

It is a super-4 number, since 4×122133330131774 (a number of 53 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (12213333013157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106666506588 + 6106666506589.

It is an arithmetic number, because the mean of its divisors is an integer number (6106666506589).

Almost surely, 212213333013177 is an apocalyptic number.

It is an amenable number.

12213333013177 is a deficient number, since it is larger than the sum of its proper divisors (1).

12213333013177 is an equidigital number, since it uses as much as digits as its factorization.

12213333013177 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 47628, while the sum is 37.

Adding to 12213333013177 its reverse (77131033331221), we get a palindrome (89344366344398).

The spelling of 12213333013177 in words is "twelve trillion, two hundred thirteen billion, three hundred thirty-three million, thirteen thousand, one hundred seventy-seven".