Base | Representation |
---|---|
bin | 1011000110111010100100… |
… | …1111011111001101001011 |
3 | 1121020121000000222020012201 |
4 | 2301232221033133031023 |
5 | 3100101101421311021 |
6 | 41550434542221031 |
7 | 2400251134160305 |
oct | 261565117371513 |
9 | 47217000866181 |
10 | 12213431432011 |
11 | 3989761704737 |
12 | 1453065584777 |
13 | 6a794c5a8a64 |
14 | 3031c1852975 |
15 | 162a75618591 |
hex | b1ba93df34b |
12213431432011 has 2 divisors, whose sum is σ = 12213431432012. Its totient is φ = 12213431432010.
The previous prime is 12213431431997. The next prime is 12213431432017. The reversal of 12213431432011 is 11023413431221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12213431432011 - 215 = 12213431399243 is a prime.
It is a super-2 number, since 2×122134314320112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12213431432017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6106715716005 + 6106715716006.
It is an arithmetic number, because the mean of its divisors is an integer number (6106715716006).
Almost surely, 212213431432011 is an apocalyptic number.
12213431432011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12213431432011 is an equidigital number, since it uses as much as digits as its factorization.
12213431432011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 12213431432011 its reverse (11023413431221), we get a palindrome (23236844863232).
The spelling of 12213431432011 in words is "twelve trillion, two hundred thirteen billion, four hundred thirty-one million, four hundred thirty-two thousand, eleven".
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