Base | Representation |
---|---|
bin | 11011110001010111110010… |
… | …101111010000100101011001 |
3 | 121000110110211121110121111011 |
4 | 123301113302233100211121 |
5 | 112002120314203040241 |
6 | 1111434211235333521 |
7 | 34504220325434341 |
oct | 3361276257204531 |
9 | 530413747417434 |
10 | 122140057471321 |
11 | 35a1034229219a |
12 | 1184768a1512a1 |
13 | 531c9b1426016 |
14 | 2223878a2bd21 |
15 | e1c223408281 |
hex | 6f15f2bd0959 |
122140057471321 has 2 divisors, whose sum is σ = 122140057471322. Its totient is φ = 122140057471320.
The previous prime is 122140057471309. The next prime is 122140057471337. The reversal of 122140057471321 is 123174750041221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 120552933715600 + 1587123755721 = 10979660^2 + 1259811^2 .
It is a cyclic number.
It is not a de Polignac number, because 122140057471321 - 211 = 122140057469273 is a prime.
It is not a weakly prime, because it can be changed into another prime (122140057471301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61070028735660 + 61070028735661.
It is an arithmetic number, because the mean of its divisors is an integer number (61070028735661).
Almost surely, 2122140057471321 is an apocalyptic number.
It is an amenable number.
122140057471321 is a deficient number, since it is larger than the sum of its proper divisors (1).
122140057471321 is an equidigital number, since it uses as much as digits as its factorization.
122140057471321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 94080, while the sum is 40.
The spelling of 122140057471321 in words is "one hundred twenty-two trillion, one hundred forty billion, fifty-seven million, four hundred seventy-one thousand, three hundred twenty-one".
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