Base | Representation |
---|---|
bin | 10001110001100001010… |
… | …000011100011111101011 |
3 | 11022202122122010100020201 |
4 | 101301201100130133223 |
5 | 130002413004204120 |
6 | 2333034324333031 |
7 | 154146330132460 |
oct | 21614120343753 |
9 | 4282578110221 |
10 | 1221402413035 |
11 | 430aa2902852 |
12 | 178871244177 |
13 | 8b2406a752c |
14 | 4318ab8d667 |
15 | 21b88b2640a |
hex | 11c6141c7eb |
1221402413035 has 16 divisors (see below), whose sum is σ = 1678699737792. Its totient is φ = 835716297600.
The previous prime is 1221402412973. The next prime is 1221402413041. The reversal of 1221402413035 is 5303142041221.
It is not a de Polignac number, because 1221402413035 - 225 = 1221368858603 is a prime.
It is a super-2 number, since 2×12214024130352 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1221402412994 and 1221402413012.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37833336 + ... + 37865605.
It is an arithmetic number, because the mean of its divisors is an integer number (104918733612).
Almost surely, 21221402413035 is an apocalyptic number.
1221402413035 is a deficient number, since it is larger than the sum of its proper divisors (457297324757).
1221402413035 is an equidigital number, since it uses as much as digits as its factorization.
1221402413035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75699414.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 1221402413035 its reverse (5303142041221), we get a palindrome (6524544454256).
The spelling of 1221402413035 in words is "one trillion, two hundred twenty-one billion, four hundred two million, four hundred thirteen thousand, thirty-five".
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