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122140433 = 254947917
BaseRepresentation
bin1110100011110…
…11011100010001
322111211101011202
413101323130101
5222231443213
620041520545
73012114362
oct721733421
9274741152
10122140433
1162a43a08
1234aa3155
131c3c625c
1412315b69
15aac9b58
hex747b711

122140433 has 4 divisors (see below), whose sum is σ = 122190900. Its totient is φ = 122089968.

The previous prime is 122140423. The next prime is 122140439. The reversal of 122140433 is 334041221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 65092624 + 57047809 = 8068^2 + 7553^2 .

It is a cyclic number.

It is not a de Polignac number, because 122140433 - 212 = 122136337 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (122140439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21410 + ... + 26507.

It is an arithmetic number, because the mean of its divisors is an integer number (30547725).

Almost surely, 2122140433 is an apocalyptic number.

It is an amenable number.

122140433 is a deficient number, since it is larger than the sum of its proper divisors (50467).

122140433 is an equidigital number, since it uses as much as digits as its factorization.

122140433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50466.

The product of its (nonzero) digits is 576, while the sum is 20.

The square root of 122140433 is about 11051.7162920517. The cubic root of 122140433 is about 496.1577945421.

Adding to 122140433 its reverse (334041221), we get a palindrome (456181654).

The spelling of 122140433 in words is "one hundred twenty-two million, one hundred forty thousand, four hundred thirty-three".

Divisors: 1 2549 47917 122140433