Base | Representation |
---|---|
bin | 10001110001100010111… |
… | …110011010011010100001 |
3 | 11022202201122100220220011 |
4 | 101301202332122122201 |
5 | 130002442344142403 |
6 | 2333041234244521 |
7 | 154150130145232 |
oct | 21614276323241 |
9 | 4282648326804 |
10 | 1221431240353 |
11 | 431008102185 |
12 | 17887aa26741 |
13 | 8b24665b80c |
14 | 43190935089 |
15 | 21b8b41ca6d |
hex | 11c62f9a6a1 |
1221431240353 has 2 divisors, whose sum is σ = 1221431240354. Its totient is φ = 1221431240352.
The previous prime is 1221431240321. The next prime is 1221431240387. The reversal of 1221431240353 is 3530421341221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 966963455649 + 254467784704 = 983343^2 + 504448^2 .
It is a cyclic number.
It is not a de Polignac number, because 1221431240353 - 25 = 1221431240321 is a prime.
It is not a weakly prime, because it can be changed into another prime (1221431240053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610715620176 + 610715620177.
It is an arithmetic number, because the mean of its divisors is an integer number (610715620177).
Almost surely, 21221431240353 is an apocalyptic number.
It is an amenable number.
1221431240353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221431240353 is an equidigital number, since it uses as much as digits as its factorization.
1221431240353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1221431240353 its reverse (3530421341221), we get a palindrome (4751852581574).
The spelling of 1221431240353 in words is "one trillion, two hundred twenty-one billion, four hundred thirty-one million, two hundred forty thousand, three hundred fifty-three".
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