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122143413310969 is a prime number
BaseRepresentation
bin11011110001011010111010…
…110000110001010111111001
3121000110210111111001221001111
4123301122322300301113321
5112002144202301422334
61111435524234520321
734504366434545401
oct3361327260612771
9530423444057044
10122143413310969
1135a118045a6196
1211848265b960a1
1353200c775975b
142223ab65c1801
15e1c36cd3b064
hex6f16bac315f9

122143413310969 has 2 divisors, whose sum is σ = 122143413310970. Its totient is φ = 122143413310968.

The previous prime is 122143413310957. The next prime is 122143413311011. The reversal of 122143413310969 is 969013314341221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 122106654835344 + 36758475625 = 11050188^2 + 191725^2 .

It is an emirp because it is prime and its reverse (969013314341221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 122143413310969 - 223 = 122143404922361 is a prime.

It is a super-2 number, since 2×1221434133109692 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (122143413310169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61071706655484 + 61071706655485.

It is an arithmetic number, because the mean of its divisors is an integer number (61071706655485).

Almost surely, 2122143413310969 is an apocalyptic number.

It is an amenable number.

122143413310969 is a deficient number, since it is larger than the sum of its proper divisors (1).

122143413310969 is an equidigital number, since it uses as much as digits as its factorization.

122143413310969 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 839808, while the sum is 49.

The spelling of 122143413310969 in words is "one hundred twenty-two trillion, one hundred forty-three billion, four hundred thirteen million, three hundred ten thousand, nine hundred sixty-nine".