Base | Representation |
---|---|
bin | 10001110001100111110… |
… | …110011111111110000001 |
3 | 11022202221100022101102101 |
4 | 101301213312133332001 |
5 | 130003124320131113 |
6 | 2333053315550401 |
7 | 154152142425241 |
oct | 21614766377601 |
9 | 4282840271371 |
10 | 1221513052033 |
11 | 43104a30053a |
12 | 1788a22bb401 |
13 | 8b25a5a46b1 |
14 | 4319b74db21 |
15 | 21b936cd2dd |
hex | 11c67d9ff81 |
1221513052033 has 2 divisors, whose sum is σ = 1221513052034. Its totient is φ = 1221513052032.
The previous prime is 1221513052021. The next prime is 1221513052049. The reversal of 1221513052033 is 3302503151221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 664016376384 + 557496675649 = 814872^2 + 746657^2 .
It is an emirp because it is prime and its reverse (3302503151221) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1221513052033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1221513051992 and 1221513052010.
It is not a weakly prime, because it can be changed into another prime (1221513052063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610756526016 + 610756526017.
It is an arithmetic number, because the mean of its divisors is an integer number (610756526017).
Almost surely, 21221513052033 is an apocalyptic number.
It is an amenable number.
1221513052033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221513052033 is an equidigital number, since it uses as much as digits as its factorization.
1221513052033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 28.
The spelling of 1221513052033 in words is "one trillion, two hundred twenty-one billion, five hundred thirteen million, fifty-two thousand, thirty-three".
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