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122151345555443 is a prime number
BaseRepresentation
bin11011110001100010010011…
…100011111000011111110011
3121000111112222021222200211212
4123301202103203320133303
5112002311423430233233
61111443315314230335
734505100133530521
oct3361422343703763
9530445867880755
10122151345555443
1135a151050a5936
12118498ba5853ab
135320a8cc38839
142224229c8d311
15e1c684400a48
hex6f18938f87f3

122151345555443 has 2 divisors, whose sum is σ = 122151345555444. Its totient is φ = 122151345555442.

The previous prime is 122151345555403. The next prime is 122151345555521. The reversal of 122151345555443 is 344555543151221.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 122151345555443 - 238 = 121876467648499 is a prime.

It is a super-3 number, since 3×1221513455554433 (a number of 43 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 122151345555391 and 122151345555400.

It is not a weakly prime, because it can be changed into another prime (122151345555403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61075672777721 + 61075672777722.

It is an arithmetic number, because the mean of its divisors is an integer number (61075672777722).

Almost surely, 2122151345555443 is an apocalyptic number.

122151345555443 is a deficient number, since it is larger than the sum of its proper divisors (1).

122151345555443 is an equidigital number, since it uses as much as digits as its factorization.

122151345555443 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7200000, while the sum is 50.

The spelling of 122151345555443 in words is "one hundred twenty-two trillion, one hundred fifty-one billion, three hundred forty-five million, five hundred fifty-five thousand, four hundred forty-three".