Base | Representation |
---|---|
bin | 11011110001100010111011… |
… | …110001000110101101000111 |
3 | 121000111121201022021121221120 |
4 | 123301202323301012231013 |
5 | 112002314314122011101 |
6 | 1111443510252245023 |
7 | 34505122634253363 |
oct | 3361427361065507 |
9 | 530447638247846 |
10 | 122152020110151 |
11 | 35a15420945869 |
12 | 11849a68470773 |
13 | 5320b69909135 |
14 | 22242916c22a3 |
15 | e1c6c3748b36 |
hex | 6f18bbc46b47 |
122152020110151 has 32 divisors (see below), whose sum is σ = 168974147317248. Its totient is φ = 78427818898560.
The previous prime is 122152020110143. The next prime is 122152020110161. The reversal of 122152020110151 is 151011020251221.
It is not a de Polignac number, because 122152020110151 - 23 = 122152020110143 is a prime.
It is a super-3 number, since 3×1221520201101513 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (122152020110111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 21982920 + ... + 26973186.
It is an arithmetic number, because the mean of its divisors is an integer number (5280442103664).
Almost surely, 2122152020110151 is an apocalyptic number.
122152020110151 is a deficient number, since it is larger than the sum of its proper divisors (46822127207097).
122152020110151 is a wasteful number, since it uses less digits than its factorization.
122152020110151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4992551.
The product of its (nonzero) digits is 400, while the sum is 24.
Adding to 122152020110151 its reverse (151011020251221), we get a palindrome (273163040361372).
The spelling of 122152020110151 in words is "one hundred twenty-two trillion, one hundred fifty-two billion, twenty million, one hundred ten thousand, one hundred fifty-one".
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