Base | Representation |
---|---|
bin | 1011000111010011000101… |
… | …1110011010000111101011 |
3 | 1121021012222122111022220220 |
4 | 2301310301132122013223 |
5 | 3100203041033341021 |
6 | 41553443535021123 |
7 | 2400603201162606 |
oct | 261646136320753 |
9 | 47235878438826 |
10 | 12220012012011 |
11 | 3991529229901 |
12 | 14543a136a7a3 |
13 | 6a845aa30c8b |
14 | 3036477d133d |
15 | 162d0d1d4cc6 |
hex | b1d3179a1eb |
12220012012011 has 4 divisors (see below), whose sum is σ = 16293349349352. Its totient is φ = 8146674674672.
The previous prime is 12220012011943. The next prime is 12220012012057. The reversal of 12220012012011 is 11021021002221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12220012012011 - 215 = 12220011979243 is a prime.
It is a super-3 number, since 3×122200120120113 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (12220012014011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2036668668666 + ... + 2036668668671.
It is an arithmetic number, because the mean of its divisors is an integer number (4073337337338).
Almost surely, 212220012012011 is an apocalyptic number.
12220012012011 is a deficient number, since it is larger than the sum of its proper divisors (4073337337341).
12220012012011 is an equidigital number, since it uses as much as digits as its factorization.
12220012012011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4073337337340.
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 12220012012011 its reverse (11021021002221), we get a palindrome (23241033014232).
The spelling of 12220012012011 in words is "twelve trillion, two hundred twenty billion, twelve million, twelve thousand, eleven".
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