Base | Representation |
---|---|
bin | 1011000111010110110001… |
… | …1011111001110001111011 |
3 | 1121021022112120211211211121 |
4 | 2301311230123321301323 |
5 | 3100212102302223003 |
6 | 41554130033010111 |
7 | 2400636542216644 |
oct | 261655433716173 |
9 | 47238476754747 |
10 | 12221001211003 |
11 | 3991996645732 |
12 | 14546186b3937 |
13 | 6a8587958b20 |
14 | 3036dcd2a6cb |
15 | 162d69e80cbd |
hex | b1d6c6f9c7b |
12221001211003 has 16 divisors (see below), whose sum is σ = 13225672908000. Its totient is φ = 11225689009920.
The previous prime is 12221001210959. The next prime is 12221001211031. The reversal of 12221001211003 is 30011210012221.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12221001211003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12221001211033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 515338 + ... + 4970671.
It is an arithmetic number, because the mean of its divisors is an integer number (826604556750).
Almost surely, 212221001211003 is an apocalyptic number.
12221001211003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12221001211003 is a deficient number, since it is larger than the sum of its proper divisors (1004671696997).
12221001211003 is a wasteful number, since it uses less digits than its factorization.
12221001211003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5486862.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 12221001211003 its reverse (30011210012221), we get a palindrome (42232211223224).
The spelling of 12221001211003 in words is "twelve trillion, two hundred twenty-one billion, one million, two hundred eleven thousand, three".
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