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122210300012113 = 671824034328539
BaseRepresentation
bin11011110010011001001101…
…100001010010011001010001
3121000201012010221012101210001
4123302121031201102121101
5112004243143300341423
61111530345313010001
734512255106251115
oct3362311541223121
9530635127171701
10122210300012113
1135a381083827a5
1211859212253901
1353264c6ba0b21
14222701d93b745
15e1de84e77cad
hex6f264d852651

122210300012113 has 4 divisors (see below), whose sum is σ = 124034334340720. Its totient is φ = 120386265683508.

The previous prime is 122210300012107. The next prime is 122210300012123. The reversal of 122210300012113 is 311210003012221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 122210300012113 - 25 = 122210300012081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (122210300012123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 912017164203 + ... + 912017164336.

It is an arithmetic number, because the mean of its divisors is an integer number (31008583585180).

Almost surely, 2122210300012113 is an apocalyptic number.

It is an amenable number.

122210300012113 is a deficient number, since it is larger than the sum of its proper divisors (1824034328607).

122210300012113 is an equidigital number, since it uses as much as digits as its factorization.

122210300012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1824034328606.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 122210300012113 its reverse (311210003012221), we get a palindrome (433420303024334).

The spelling of 122210300012113 in words is "one hundred twenty-two trillion, two hundred ten billion, three hundred million, twelve thousand, one hundred thirteen".

Divisors: 1 67 1824034328539 122210300012113