Base | Representation |
---|---|
bin | 10001110010001011000… |
… | …010010100100001100001 |
3 | 11022211110111001210201111 |
4 | 101302023002110201201 |
5 | 130010331424302231 |
6 | 2333232044103321 |
7 | 154202601051505 |
oct | 21621302244141 |
9 | 4284414053644 |
10 | 1222103353441 |
11 | 431322534743 |
12 | 178a27b34b41 |
13 | 8b322985979 |
14 | 43215cd0305 |
15 | 21bca4324b1 |
hex | 11c8b094861 |
1222103353441 has 2 divisors, whose sum is σ = 1222103353442. Its totient is φ = 1222103353440.
The previous prime is 1222103353409. The next prime is 1222103353511. The reversal of 1222103353441 is 1443533012221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 670654534225 + 551448819216 = 818935^2 + 742596^2 .
It is an emirp because it is prime and its reverse (1443533012221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1222103353441 - 25 = 1222103353409 is a prime.
It is not a weakly prime, because it can be changed into another prime (1222103353241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611051676720 + 611051676721.
It is an arithmetic number, because the mean of its divisors is an integer number (611051676721).
Almost surely, 21222103353441 is an apocalyptic number.
It is an amenable number.
1222103353441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1222103353441 is an equidigital number, since it uses as much as digits as its factorization.
1222103353441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1222103353441 its reverse (1443533012221), we get a palindrome (2665636365662).
The spelling of 1222103353441 in words is "one trillion, two hundred twenty-two billion, one hundred three million, three hundred fifty-three thousand, four hundred forty-one".
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