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122211210201120 = 2533571398445521
BaseRepresentation
bin11011110010011010000011…
…110001011000100000100000
3121000201021111100212210101000
4123302122003301120200200
5112004302024302413440
61111531015505312000
734512316500604305
oct3362320361304040
9530637440783330
10122211210201120
1135a38535134217
1211859427035600
1353266106240c1
1422270a878b0ac
15e1ded9d18730
hex6f2683c58820

122211210201120 has 192 divisors, whose sum is σ = 433763733070080. Its totient is φ = 32130646732800.

The previous prime is 122211210201079. The next prime is 122211210201127. The reversal of 122211210201120 is 21102012112221.

122211210201120 is a `hidden beast` number, since 1 + 2 + 221 + 121 + 0 + 201 + 120 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 122211210201093 and 122211210201102.

It is not an unprimeable number, because it can be changed into a prime (122211210201127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 198916041 + ... + 199529480.

It is an arithmetic number, because the mean of its divisors is an integer number (2259186109740).

Almost surely, 2122211210201120 is an apocalyptic number.

122211210201120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

122211210201120 is an abundant number, since it is smaller than the sum of its proper divisors (311552522868960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

122211210201120 is a wasteful number, since it uses less digits than its factorization.

122211210201120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 398445616 (or 398445602 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 18.

Adding to 122211210201120 its reverse (21102012112221), we get a palindrome (143313222313341).

The spelling of 122211210201120 in words is "one hundred twenty-two trillion, two hundred eleven billion, two hundred ten million, two hundred one thousand, one hundred twenty".