Base | Representation |
---|---|
bin | 10110110000111001… |
… | …01000101111010011 |
3 | 1011112201120101111221 |
4 | 23120130220233103 |
5 | 200012124221042 |
6 | 5340413145511 |
7 | 611566335661 |
oct | 133034505723 |
9 | 34481511457 |
10 | 12221320147 |
11 | 5201686793 |
12 | 2450a8b297 |
13 | 11c9c750aa |
14 | 83d18dc31 |
15 | 4b7ddbd67 |
hex | 2d8728bd3 |
12221320147 has 2 divisors, whose sum is σ = 12221320148. Its totient is φ = 12221320146.
The previous prime is 12221320117. The next prime is 12221320169. The reversal of 12221320147 is 74102312221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12221320147 - 211 = 12221318099 is a prime.
It is a super-2 number, since 2×122213201472 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12221320117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110660073 + 6110660074.
It is an arithmetic number, because the mean of its divisors is an integer number (6110660074).
Almost surely, 212221320147 is an apocalyptic number.
12221320147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221320147 is an equidigital number, since it uses as much as digits as its factorization.
12221320147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 12221320147 its reverse (74102312221), we get a palindrome (86323632368).
The spelling of 12221320147 in words is "twelve billion, two hundred twenty-one million, three hundred twenty thousand, one hundred forty-seven".
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